(3t^2-2t+4)+(2t^2+5t-3)=0

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Solution for (3t^2-2t+4)+(2t^2+5t-3)=0 equation: 



(3t^2-2t+4)+(2t^2+5t-3)=0

We get rid of parentheses

3t^2+2t^2-2t+5t+4-3=0

We add all the numbers together, and all the variables

5t^2+3t+1=0

a = 5; b = 3; c = +1;
Δ = b2-4ac
Δ = 32-4·5·1
Δ = -11
Delta is less than zero, so there is no solution for the equation

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